1-(8/x^2)=-4/x^4

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Solution for 1-(8/x^2)=-4/x^4 equation:


D( x )

x^4 = 0

x^2 = 0

x^4 = 0

x^4 = 0

1*x^4 = 0 // : 1

x^4 = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

1-(8/(x^2)) = -4/(x^4) // + -4/(x^4)

1-(8/(x^2))-(-4/(x^4)) = 0

4*x^-4-8*x^-2+1 = 0

t_1 = x^-2

4*t_1^2-8*t_1^1+1 = 0

4*t_1^2-8*t_1+1 = 0

DELTA = (-8)^2-(1*4*4)

DELTA = 48

DELTA > 0

t_1 = (48^(1/2)+8)/(2*4) or t_1 = (8-48^(1/2))/(2*4)

t_1 = (4*3^(1/2)+8)/8 or t_1 = (8-4*3^(1/2))/8

t_1 = (8-4*3^(1/2))/8

x^-2-((8-4*3^(1/2))/8) = 0

1*x^-2 = (8-4*3^(1/2))/8 // : 1

x^-2 = (8-4*3^(1/2))/8

-2 < 0

1/(x^2) = (8-4*3^(1/2))/8 // * x^2

1 = ((8-4*3^(1/2))/8)*x^2 // : (8-4*3^(1/2))/8

8*(8-4*3^(1/2))^-1 = x^2

x^2 = 8*(8-4*3^(1/2))^-1 // ^ 1/2

abs(x) = 2*2^(1/2)*(8-4*3^(1/2))^(-1/2)

x = 2*2^(1/2)*(8-4*3^(1/2))^(-1/2) or x = -(2*2^(1/2)*(8-4*3^(1/2))^(-1/2))

t_1 = (4*3^(1/2)+8)/8

x^-2-((4*3^(1/2)+8)/8) = 0

1*x^-2 = (4*3^(1/2)+8)/8 // : 1

x^-2 = (4*3^(1/2)+8)/8

-2 < 0

1/(x^2) = (4*3^(1/2)+8)/8 // * x^2

1 = ((4*3^(1/2)+8)/8)*x^2 // : (4*3^(1/2)+8)/8

8*(4*3^(1/2)+8)^-1 = x^2

x^2 = 8*(4*3^(1/2)+8)^-1 // ^ 1/2

abs(x) = 2*2^(1/2)*(4*3^(1/2)+8)^(-1/2)

x = 2*2^(1/2)*(4*3^(1/2)+8)^(-1/2) or x = -(2*2^(1/2)*(4*3^(1/2)+8)^(-1/2))

x in { 2*2^(1/2)*(8-4*3^(1/2))^(-1/2), -(2*2^(1/2)*(8-4*3^(1/2))^(-1/2)), 2*2^(1/2)*(4*3^(1/2)+8)^(-1/2), -(2*2^(1/2)*(4*3^(1/2)+8)^(-1/2)) }

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